今天从一个文件中拷贝了一个formpanel的配置，用以下代码提交

fp.getForm().submit({
                    url: GURLBase + "/EXEC/" + GTrackID + "/" + GAppID+"?op=addMenuItem&page=menuitem&SessionId="+GMySession,
                    method: ‘POST’,
                    scope: this,
                    params: {                 
                    },
                    success: function(form, action) {
                        win.close();
                        store.reload();

                    },
                    failure: function(form, action) {
                        if (!fp.getForm().isValid()) {
                            return;
                        }
                        Ext.Msg.alert(‘系统提示’, ‘<br/> 操作失败,请重新操作’);
                    }

                }); //end submit

提交后，发现，firebug竟然没有post的过程数据，在intraweb的断点中，发现request的contentfields数据竟然是这样的：

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Content-Disposition: form-data; name="id"

67

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Content-Disposition: form-data; name="cname"

查看注册清单

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Content-Disposition: form-data; name="ename"

view report

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Content-Disposition: form-data; name="parentid"

0

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Content-Disposition: form-data; name="leaf"

1

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Content-Disposition: form-data; name="page"

rep_list

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Content-Disposition: form-data; name="icon"

bg_waitIcon

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Content-Disposition: form-data; name="module"

report

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Content-Disposition: form-data; name="permcode"

024

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原因：

经过仔细查看，原来formpanel竟然配置了

fileUpload:true

看来，拷贝来的代码，还是应该好好的检查的，浪费了我一天的时间啊～～～